Consider the following circuit :
Switch is closed at t = 0
Find i(0 +)
At t = 0, capacitor will be short.
So i(0) = V / R.
In question no. 1, which of the following is true ?
At t = 0+, capacitor will be short.
So, i(0) = ic = V/R.
The impulse response of the system described by the differential equation
The current at a given point in certain circuit is given as function of time as
i(t) = d – 3+t, t = 99 sec & t = 102 sec is
What would be the power given by source V2 ?
Among two voltage source, only 10V source will deliver power to 5 V voltage source. Power given by V2 = – V2 / R = - 5 W.
Two combination of similar inductors are show below. Which one has more inductance between A & B
Here in circuit B, mutual inductance is additive. So in circuit 2 has more inductance.
Consider the following circuit. What is the value of i ?
Voltage source will offer zero resistance path to current. So net current in 1 Ω resistance depends only voltage source. So current i = 5 × i = 5 A.
In above question, power given in the SV source is
Source current = 5 – 1 = 4 Amp.
Power given by the 5 V source = 5 × 4 = 20 W.
Total power consumed in the circuit below is 10 W. Find x.
Total power consumed = x2× 2 + 22/2
⇒ 10 W = 2 ×x2 + 2
Therefore, x = 2 A.
If Vout = 1V for 1 KHz input then what would be Vout for 10 KHz for same input ?
So a frequency of 1 MHz, the gain is 1 or 0 dB.
A battery of E volts is supplying a steady current to a series circuit of total resistance R ohm & inductance L Henry. A part R1 of the total resistance is suddenly short circuited.
Find the expression for current flowing through the battery subsequent to the operation
Let, after t sec, the current is i.
At t = 0, i = E / R,
In above question, determine the current if E = 100 V, R = 20 ohm, R1 = 10 Ohm & L = 2 H at 0.5 sec after short circuit
A first order linear system is initially relaxed. For a unit step signal u(t), the response (1 – e - 3t ) for t > 0. If the signal 3u(t) + δ (T) is applied to same initially relaxed system, the response will be
Using the principal of superposition so output due to 3u(t) + δ(t) is
= 3 – 3e – 3t + 3e –3t
= 3 = 3u(t) .
A 10 V battery with an internal resistance of 1 Ω is connected across a non-linear load whose V. I characteristic are 7i = V2 + 2V. The current delivered by the battery is
Voltage across the non linear load = 10 – 1× I
So, 7I = V2 + 2V
I = 5A.
Find the total power absorbed by the resistor in the given circuit.
Equivalent circuit can be drawn,
P = I2R.
In the circuit shown below if I = 2A then find V ?
The circuit can be redrawn as
⇒ V = ½ × 2 + ½ × 2 =2 V.
What is I1 in the given circuit ?
Voltage across 2 ohm resistance carrying current I1 is
= (6 × 1) / 4 + (3 × 1) / 3 = 3V.
What is Va in the below circuit
Applying superposition theorem,
If L & C both are doubled than damping in above circuit will be
Here if L & C both are doubled that means
A capacitor is charged by a constant 10mA current sources which is turned on for 1 second. Assuming the capacitor is initially charge free; determine the charge delivered to & the power supplied by the source if the capacitor has a value of 1mF
: V = q / C $amp; q = i.t
Power delivered P =Vi = qi / C.